actually make _DEBUG useful

typescript
Drake 2 years ago
parent 3848a02879
commit ad367811ca

@ -45,27 +45,17 @@ const log = makeLogger(console.log);
const warn = makeLogger(console.warn);
const error = makeLogger(console.error);
const trace = makeLogger(console.trace);
/*const group = (msg, loc, sublogs) => {
// start group
getLogger(console.group)(msg, loc);
for (const sublog of sublogs) {
const logFunc = getLogger(
sublog.length === 3 ? sublog[2] : "log",
true
);
logFunc(sublog[0], sublog[1]);
}
console.groupEnd();
};*/
const debug = makeLogger((...args) => {
//#if _DEBUG
console.log(...args)
//#endif
})
export default {
log,
warn,
error,
trace,
debug,
makeLogger
};

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